Subject

    Bank Exam

    Topic

    Trust Bank Ltd. - Management Trainee Officer - 2016

    Evaluate: (2.39)2  −(1.61)2  2.39−1.61\frac{{{{(2.39)}^{2\;}} - {{(1.61)}^{2\;}}}}{{2.39 - 1.61}}

    ক)
    2
    খ)
    4
    গ)
    6
    ঘ)
    8
    ঙ)
    None

    Explanation

    Solution: (2.39)2  −(1.61)2  2.39−1.61=(2.39+1.61)(2.39−1.61)(2.39−1.61)\frac{{{{(2.39)}^{2\;}} - {{(1.61)}^{2\;}}}}{{2.39 - 1.61}} = \frac{{(2.39 + 1.61)(2.39 - 1.61)}}{{(2.39 - 1.61)}} = 4

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