Subject

    Quantitative Aptitude

    Topic

    Areas & Volumes

    The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.

    ক)
    12
    খ)
    24
    গ)
    36
    ঘ)
    48

    Explanation

    side of first square = 40/4 =10cm side of second square = 32/4 = 8cm area of third squre = 10² - 8² = 36 sq cm side of third square = 36\sqrt{36} = 6 cm required perimeter = 6*4 = 24cm

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