Subject
Quantitative Aptitude
Topic
Areas & Volumes
A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
ক)
2 : 1খ)
3 : 2গ)
25 : 18ঘ)
27 : 20Explanation
Volume of the large cube = (33 + 43 + 53) = 216 cm3. Let the edge of the large cube be a. So, a3 = 216 =>a = 6 cm. So, Required ratio =(6 x (33+42+52))/(6 x 62) = 50/36 = 25:18Related questions
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