Subject

    Quantitative Aptitude

    Topic

    Areas & Volumes

    The percentage increase in the area of a rectangle, if each of its sides is increased by 20%

    ক)
    22%
    খ)
    33%
    গ)
    44%
    ঘ)
    55%

    Explanation

    Let original length = x metres and original breadth = y metres. Original area = xy sq.m Increased length  = 120100\frac{120}{100}  and Increased breadth = 120100\frac{120}{100} New area = 120100x∗120100y=3625xy  m2\frac{120}{100}x\ast\frac{120}{100}y=\frac{36}{25}xy\;m^2 The difference between the Original area  and New area  is: 3625xy−xy\frac{36}{25}xy-xy 1125xy\frac{11}{25}xy Increase % = (1125xyxy)∗100\left(\frac{\displaystyle\frac{11}{25}xy}{xy}\right)\ast100 = 44%

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