The number of chocolates with Rani when m… | Answer

Subject

Quantitative Aptitude

Topic

Algebra

The number of chocolates with Rani when multiplied by 12, gives the number of chocolates with Kajol, which are as much above 130 as the number of chocolates with Rani are below 130. The average of the number of chocolates with Rani and Kajol is:
Reading

ক)

140

খ)

130

গ)

175

ঘ)

112

ঙ)

None of these

Explanation

Let number of chocolates with Rani = x, then according to the question, Number of chocolates with Kajol = 12x, We are given that, 12x – 130 = 130 – x ⇒ 13x = 260, ⇒ x = 20, ∴ Number of chocolates with Kajol = 12 × 20 = 240 ∴ Total number of chocolates with Rani and Kajol together = 240 + 20 = 260 We know that, formula for average-

\Rightarrow \left\{ {{A_E} = \frac{{{S_E}}}{{{n_E}}}\;or\;{S_E} = {A_E} \times {n_E}} \right\}

Where, S E = sum of entities, n E = number of entities, A E = Average of entities. Hence, average number of chocolates with Rani and Kajol together = (20+240)/2=130 Alternatively- [Simply we are given that no. of chocolates with Rani and Kajol are equidistant from 130, one is less and other is more by the same no, hence average would be 130 itself.]

\frac{a}{3} = \frac{b}{4} = \frac{c}{7}

then what would be the value of

\frac{{a + b + c}}{a}

?Multiplication and difference of two numbers are 93 and 28 respectively. Find the difference of reciprocals of the numbers.if

{P^2} + {1 \over {{P^2}}} = 7

, then find the value of

{P^2} - {1 \over {{P^2}}}.

In following question, two equations are given, you have to solve them and choose the correct option: x2– 3x – 4 = 0, y2– 4 = 0 In following question, two equations are given, you have to solve them and chose the correct option: x2+ 11x + 30 = 0, y2+ 7y + 12 = 0 In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘l’ and ‘m’ and mark correct answer. I. (125)1/3l – (1331)1/3= 4 × (729)1/6+ (1024)1/10II. (m)2– (15625)1/3= 0 Direction: In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I: x - √121 = 0 II: y2- 121 = 0 The number of solutions of x2+ 4|x| + 5 = 0 is

The number of chocolates with Rani when multiplied by 12, gives the number of chocolates with Kajol, which are as much above 130 as the number of chocolates with Rani are below 130. The average of the number of chocolates with Rani and Kajol is:Reading

The number of chocolates with Rani when multiplied by 12, gives the number of chocolates with Kajol, which are as much above 130 as the number of chocolates with Rani are below 130. The average of the number of chocolates with Rani and Kajol is:

Explanation

Related questions

Find Tutors

The number of chocolates with Rani when multiplied by 12, gives the number of chocolates with Kajol, which are as much above 130 as the number of chocolates with Rani are below 130. The average of the number of chocolates with Rani and Kajol is:
Reading