Subject
Quantitative Aptitude
Topic
Algebra
In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘l’ and ‘m’ and mark correct answer.
I. (125)1/3l – (1331)1/3= 4 × (729)1/6+ (1024)1/10II. (m)2– (15625)1/3= 0
In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘l’ and ‘m’ and mark correct answer. I. (125)1/3l – (1331)1/3= 4 × (729)1/6+ (1024)1/10II. (m)2– (15625)1/3= 0
ক)
l > mখ)
l ≥ mগ)
l < mঘ)
l ≤ mঙ)
l = m or the relation cannot be determinedExplanation
We solve both equations separately Equation I: (125) 1/3 l – (1331) 1/3 = 4 × (729) 1/6 + (1024) 1/10 ⇒ 5l – 11 = 4 × 3 + 2 ⇒ 5l = 14 + 11 ⇒ l = 25/5 ⇒ l = 5 Equation II: (m) 2 – (15625) 1/3 = 0 ⇒ (m) 2 = (15625) 1/3 ⇒ m 2 = 25 ⇒ m 2 – 25 = 0 By using the formula: a 2 – b 2 = (a + b) (a – b) ⇒ m = ± 5 Comparing values of l and m, we obtain l ≥ mRelated questions
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