Subject

    Quantitative Aptitude

    Topic

    Areas & Volumes

    The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is

    ক)
    5100 sq.m
    খ)
    4870 sq.m
    গ)
    4987 sq.m
    ঘ)
    4442 sq.m

    Explanation

    Let the breadth of floor be 'b' m. Then, length of the floor is 'l = (b + 25)' Area of the rectangular floor = l x b = (b + 25) × b According to the question, (b + 15) (b + 8) = (b + 25) × b b2  +  8b  +  15b  +  120  =  b2\mathrm b^2\;+\;8\mathrm b\;+\;15\mathrm b\;+\;120\;=\;\mathrm b^2 2b = 120 b = 60 m. l = b + 25 = 60 + 25 = 85 m . Area of the floor = 85 × 60 = 5100 sq.m .

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