The diagonal of a rectangle is \( 41 \) c… | Answer | TuitionWave

Subject

Quantitative Aptitude

Topic

Areas & Volumes

The diagonal of a rectangle is $\sqrt{41}$ cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Reading

ক)

18

খ)

28

গ)

38

ঘ)

48

Explanation

\sqrt{\left(l^2+b^2\right)}=\sqrt{41}

(or)

l^2+b^2=41

Also ,

lb=20

\left(l+b\right)^2=l^{2+}b^2+2lb

= 41 + 40 = 81 (l + b) = 9. Perimeter = 2(l + b) = 18 cm.

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