Raman has some 50-paisa coins, some 2-rup… | Answer

Subject

Quantitative Aptitude

Topic

Algebra

Raman has some 50-paisa coins, some 2-rupee coins, some 1-rupee coins and some 5-rupee coins. The value of all the coins is Rs. 50. Number of 2-rupee coins is 5 more than that of the 5 rupee coins. 50 paisa coins are double in number than 1 rupee coins. Value of 50-paisa coins and 1-rupee coins is Rs. 26. How many 2-rupee coins does he have?
Reading

ক)

খ)

গ)

ঘ)

Cannot be determined

ঙ)

None of these

Explanation

Number of 5 rupee coin = y, value = Rs. 5y Number of 2 rupee coins = 5 + y, value = Rs. 10 + 2y Number of 1 rupee coins = x, value = Rs. x Number of 50 paisa coins = 2x, value = Rs. x According to the problem, Value of 50-paisa coins and 1-rupee coins is Rs. 26 Hence, x + x = 26 ⇒ x = 13 Hence, number of 1 rupee coins = 13 Number of 50 paisa coins = 26 The value of all the coins is Rs. 50. Hence, 26 + 5y + 10 + 2y = 50 ⇒ 7y + 36 = 50 ⇒ 7y = 14 ⇒ y = 2 Number of 2 rupee coins = y + 5 = 7

\frac{a}{3} = \frac{b}{4} = \frac{c}{7}

then what would be the value of

\frac{{a + b + c}}{a}

?Multiplication and difference of two numbers are 93 and 28 respectively. Find the difference of reciprocals of the numbers.if

{P^2} + {1 \over {{P^2}}} = 7

, then find the value of

{P^2} - {1 \over {{P^2}}}.

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Explanation

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