Subject
Quantitative Aptitude
Topic
Algebra
In the following question,two equations are given. On their basis you have to determine the relation between x and y and then give answer
I. 3x2– 7x + 2 = 0
II. 2y2– 11y + 15 = 0
In the following question,two equations are given. On their basis you have to determine the relation between x and y and then give answer I. 3x2– 7x + 2 = 0 II. 2y2– 11y + 15 = 0
ক)
x < yখ)
x > yগ)
x ≤ yঘ)
x ≥ yঙ)
x = yExplanation
3x 2 - 7x + 2 = 0 ⇒ 3x 2 - 6x - x + 2 = 0 ⇒ 3x (x - 2) - 1 (x - 2) = 0 ⇒ (3x - 1) (x - 2) = 0 ⇒ 3x - 1 = 0 ⇒ 3x = 1 ⇒ x = 1/3 or, x - 2 = 0 ⇒ x = 2 Equation 2: 2y 2 - 11y + 15 = 0 ⇒ 2y 2 - 6y - 5y +15 = 0 ⇒ 2y (y - 3) - 5 (y - 3) = 0 ⇒ (2y - 5) (y - 3) = 0 ⇒ (2y - 5) = 0 ⇒ y = 5/2 Also (y - 3) = 0 ⇒ y = 3 Now comparing x and y: x = 1/3 is smaller than 5/2 and 3 x= 2 is smaller than 3 and 5/2 Thus we see that x is smaller than yRelated questions
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