Subject
Quantitative Aptitude
Topic
Algebra
In the following question, there are two equations. Solve them and give answer
I. 20P2– 17P + 3 = 0
II. 20Q2– 9Q + 1 = 0
In the following question, there are two equations. Solve them and give answer I. 20P2– 17P + 3 = 0 II. 20Q2– 9Q + 1 = 0
ক)
P < Qখ)
P > Qগ)
P ≤ Qঘ)
P ≥ Qঙ)
P = QExplanation
I. 20P 2 – 17P + 3 = 0 On doing factorization ⇒ 20P 2 – 5P – 12P + 3 = 0 ⇒ 5P (4P – 1) – 3 (4P – 1) = 0 ⇒ (4P – 1) (5P – 3) = 0 ⇒ P = 1/4, 3/5 ⇒ P = 0.25, 0.60 II. 20Q 2 – 9Q + 1 = 0 On doing factorization ⇒ 20Q 2 – 5Q – 4Q + 1 = 0 ⇒ 5Q (4Q – 1) – 1 (4Q – 1) = 0 ⇒ (4Q – 1) (5Q – 1) = 0 ⇒ Q = 1/4, 1/5 ⇒ Q = 0.25, 0.20 On taking Q = 0.25 ⇒ P ≥ Q (for both the values of P) . . . . equation 1 On taking Q = 0.20 ⇒ P > Q (for both the values of P) . . . . equation 2 From equation 1 and 2 P ≥ QRelated questions
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