Subject

    Quantitative Aptitude

    Topic

    Algebra

    In the following question, there are two equations. Solve them and give answer I. 20P2+ 31P + 12 = 0  II. 21Q2+ 23Q + 6 = 0

    ক)
    P < Q
    খ)
    P > Q
    গ)
    P ≤ Q
    ঘ)
    P ≥ Q
    ঙ)
    P = Q

    Explanation

    I. 20P 2 + 31P + 12 = 0 On doing factorization ⇒ 20P 2 + 15P + 16P + 12 = 0 ⇒ 5P (4P + 3) + 4 (4P + 3) = 0 ⇒ (4P + 3) (5P + 4) = 0 ⇒ P = -3/4, -4/5 ⇒ P = - 0.75, -0.80 II. 21Q 2 + 23Q + 6 = 0 On doing factorization ⇒ 21Q 2 + 9Q + 14Q + 6 = 0 ⇒ 3Q (7Q + 3) + 2 (7Q + 3) = 0 ⇒ (7Q + 3) (3Q + 2) = 0 ⇒ Q = −37  ,  −23- \frac{3}{7}\;,\; - \frac{2}{3} ⇒ Q = - 0.43, -0.66 On taking Q = - 0.43 ⇒ P < Q (for both the values of P)                            . . . . equation 1 On taking Q = − 0.66 −0.66 ⇒ P < Q (for both the values of P)                            . . . . equation 2 From equation 1 and 2 P < Q

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