Subject

    Quantitative Aptitude

    Topic

    Algebra

    In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. 4x2– 7x – 2 = 0 II. 6y2+ 11y + 4 = 0

    ক)
    x > y
    খ)
    x ≥ y
    গ)
    x < y
    ঘ)
    x ≤ y
    ঙ)
    x = y or the relation cannot be determined

    Explanation

    We will solve both the equations separately. Equation I: 4x 2 – 7x – 2 = 0 ⇒ 4x 2 – 8x + x – 2 = 0 ⇒ 4x(x – 2) + 1(x – 2) = 0 ⇒ (4x + 1) (x – 2) = 0 ⇒ x = - 1/4 = - 0.25 or x = 2 Equation II: 6y 2 + 11y + 4 = 0 ⇒ 6y 2 + 8y + 3y + 4 = 0 ⇒ 3y (2y + 1) + 4(2y + 1) = 0 ⇒ (3y + 4) (2y + 1) = 0 ⇒ y = - 4/3 = - 1.33 or, y = - 1/2 = - 0.5 Comparing the values of x and y we get, x > y

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