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    Subject

    Quantitative Aptitude

    Topic

    Algebra

    In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. (x7/5÷ 9) = 169 ÷ x3/5II. y1/4× y1/4× 7 = 273 ÷ y1/2

    ক)
    x > y
    খ)
    x ≥ y
    গ)
    x< y
    ঘ)
    x ≤ y
    ঙ)
    x = y or the relation cannot be determined

    Explanation

    We will solve both the equations separately. Equation I: (x 7/5 ÷ 9) = 169 ÷ x 3/5 ⇒(x)759=169x35\Rightarrow \frac{{{{(x)}^{\frac{7}{5}}}}}{9} = \frac{{169}}{{{x^{\frac{3}{5}}}}} ⇒ x 10/5 = 9 × 169 ⇒ x 2 = 9 × 169 ⇒ x = + (3 × 13), - (3 × 13) ⇒ x = +39 or – 39 Equation II: y 1/4 × y 1/4 × 7 = 273 ÷ y 1/2 ⇒ y 1/4 × y 1/4 × 7 = 273/y 1/2 ⇒ y = 273/7 = 39 Comparing the values of x and y we get, x ≤ y

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