Subject
Quantitative Aptitude
Topic
Algebra
In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer
I. x2– 6x = 7
II. 2y2+ 13y + 15 = 0
In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer I. x2– 6x = 7 II. 2y2+ 13y + 15 = 0
ক)
x < yখ)
x > yগ)
x ≤ yঘ)
x ≥ yঙ)
x = yExplanation
Equation 1: x 2 – 6x = 7 ⇒ x 2 – 6x – 7= 0 ⇒ x 2 – 7x + x – 7= 0 ⇒ x (x - 7) + 1 (x - 7) = 0 ⇒ (x + 1) (x - 7) = 0 ⇒ x + 1= 0 or, x – 7 = 0 ⇒ x= -1 or, x = 7 Equation 2: 2y 2 + 13y + 15 = 0 ⇒ 2y 2 + 10y + 3y + 15 = 0 ⇒ 2y (y +5) + 3 (y + 5) = 0 ⇒ (y + 5) (2y + 3) = 0 ⇒ y + 5 = 0 or, 2y + 3= 0 ⇒ y = -5 or, y = -3/2 Now comparing x and y: x = -1 is greater than both -5 and - 3/2 x= 7 is greater than both – 5 and - 3/2 Therefore, x is greater than yRelated questions
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