Subject
Quantitative Aptitude
Topic
Algebra
In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer
I . x2– 5x + 6 = 0
II. Y2+ y – 6 = 0
In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer I . x2– 5x + 6 = 0 II. Y2+ y – 6 = 0
ক)
x < yখ)
x > yগ)
x ≤ yঘ)
x ≥ yঙ)
x = yExplanation
We will separately solve both equations. Equation 1: x 2 - 5x + 6 = 0 ⇒ x 2 - 2x - 3x + 6 = 0 ⇒ x (x - 2) -3 (x - 2) = 0 ⇒ (x - 2) × (x - 3) = 0 ⇒ x = 2 or, x = 3 Equation 2: y 2 + y - 6 = 0 ⇒ y 2 + 3y - 2y - 6 = 0 ⇒ y (y + 3) - 2 (y + 3) = 0 ⇒ (y + 3) × (y - 2) = 0 ⇒ y = 2 or, y = -3 x & y both have one common value. That is 2. So we can say x = y Another value of y (y = -3) is less than another value of x (x = 3) So we can say y < x Combining both x ≥ yRelated questions
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II: y2- 121 = 0The number of solutions of x2+ 4|x| + 5 = 0 is
