In the following question, one or two equ… | Answer

Subject

Quantitative Aptitude

Topic

Algebra

ক)

x > y

খ)

x ≥ y

গ)

x < y

ঘ)

x ≤ y

ঙ)

x = y or the relation cannot be determined

We will solve both the equations separately. Equation I: 9x – 15.45 = 54.55 + 4x ⇒ 9x – 4x = 70 ⇒ 5x = 70 ⇒ x = 14 Equation II:

\begin{array}{l} \sqrt {y + 155} - \sqrt {36} = \sqrt {49} \\ \Rightarrow \sqrt {y + 155} - 6 = 7\\ \Rightarrow \sqrt {y + 155} = 13 \end{array}

On squaring both sides, y + 155 = 169 ⇒ y = 169 – 155 ⇒ y = 14 Comparing the values of x and y, we get, x = y

\frac{a}{3} = \frac{b}{4} = \frac{c}{7}

\frac{{a + b + c}}{a}

{P^2} + {1 \over {{P^2}}} = 7

{P^2} - {1 \over {{P^2}}}.

In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. 9x – 15.45 = 54.55 + 4x II. y+155−36=49\sqrt {y + 155} - \sqrt {36} = \sqrt {49}y+155​−36​=49​