In the following question, one or two equ… | Answer | TuitionWave

Subject

Quantitative Aptitude

Topic

Algebra

In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. $\frac{{15 \times 4}}{{{x^{4/7}}}} - \frac{{8 \times 3}}{{{x^{4/7}}}} = {x^{10/7}}$ II. y3+ 783 = 999
Reading

ক)

x > y

খ)

x ≥ y

গ)

x < y

ঘ)

x ≤ y

ঙ)

x = y or the relation cannot be determined

Explanation

We will solve both the equations separately. Equation I:

\begin{array}{l} \frac{{15 \times 4}}{{{x^{\frac{4}{7}}}}} - \frac{{8 \times 3}}{{{x^{\frac{4}{7}}}}} = {x^{\frac{{10}}{7}}}\\ \Rightarrow \;\frac{{60}}{{{x^{4/7}}}} - \frac{{24}}{{{x^{4/7}}}} = {x^{10/7}}\\ \Rightarrow \;\frac{{36}}{{{x^{4/7}}}} = {x^{10/7}}\\ \Rightarrow \;36 = {x^{\frac{{10}}{7} + \frac{4}{7}}}\\ \Rightarrow \;36 = {x^2} \end{array}

⇒ x = ± 6 Equation II: y 3 + 783 = 999 ⇒ y 3 = 999 – 783 ⇒ y 3 = 216 ⇒ y = 6 Comparing the values of x and y, we get, x ≤ y

\frac{a}{3} = \frac{b}{4} = \frac{c}{7}

then what would be the value of

\frac{{a + b + c}}{a}

?Multiplication and difference of two numbers are 93 and 28 respectively. Find the difference of reciprocals of the numbers.if

{P^2} + {1 \over {{P^2}}} = 7

, then find the value of

{P^2} - {1 \over {{P^2}}}.

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