Subject
Quantitative Aptitude
Topic
Algebra
In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘a’ and ‘b’ and mark correct answer.
I. a√25 + 2b = √961
II. 3a + (2401)1/4b = 36
In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘a’ and ‘b’ and mark correct answer. I. a√25 + 2b = √961 II. 3a + (2401)1/4b = 36
ক)
a > bখ)
a ≥ bগ)
a < bঘ)
a ≤ bঙ)
a = b or the relation cannot be determinedExplanation
We will solve both the equations separately. Equation I: a√25 + 2b = √961 Here √25 can only be evaluated as 5 ⇒ 5a + 2b = 31 Equation II: 3a + (2401) 1/4 b = 36 ⇒ 3a + 7b = 36 Multiplying the simplified values of equation (I) by 3 and that of (II) by 5, we get, b = 3 Putting this value of y in the simplified value of equation (I), we get a = 5 ∴ a > bRelated questions
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