Subject

    Quantitative Aptitude

    Topic

    Algebra

    In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer I. 3x2+ 7x = 6 II. 6(2y2+ 1) = 17y

    ক)
    x < y
    খ)
    x > y
    গ)
    x ≤  y
    ঘ)
    x ≥ y
    ঙ)
    x = y

    Explanation

    3x 2 + 7x = 6 ⇒ 3x 2 + 7x - 6 = 0 ⇒ 3x 2 + 9x - 2x - 6 = 0 ⇒ 3x (x + 3) - 2 (x + 3) = 0 ⇒ (3x - 2) (x + 3) = 0 ⇒ 3x - 2 = 0 or x + 3 = 0 ⇒ x= 2/3 or -3 Equation 2: 6(2y 2 + 1) = 17y ⇒ 12y 2 + 6 = 17y ⇒ 12y 2 – 17y + 6 = 0 ⇒12y 2 – 9y – 8y + 6 = 0 ⇒ 3y (4y- 3) – 2 (4y - 3) = 0 ⇒ (3y- 2) (4y - 3) = 0 ⇒ 3y – 2 = 0 and 4y - 3 = 0 ⇒ y = 2/3 and 3/4 Comparing values of x and y x ≤ y

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