Subject

    Quantitative Aptitude

    Topic

    Algebra

    In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer I.  x2+ 3x + 2 = 0       II. 2y2= 5y

    ক)
    x < y
    খ)
    x > y
    গ)
    x ≤  y
    ঘ)
    x ≥ y
    ঙ)
    x = y

    Explanation

    We will separately solve both equations. Equation 1: x 2 + 3x + 2 = 0 ⇒ x 2 + 2x + x + 2 = 0 ⇒ x (x + 2) + 1 (x + 2) = 0 ⇒ (x + 2) × (x + 1) = 0 ⇒ x = -2 or, x = -1 Equation 2: 2y 2 = 5y ⇒ 2y 2 – 5y = 0 ⇒2y×(y−52)=0\Rightarrow 2y \times \left( {y - \frac{5}{2}} \right) = 0 ⇒ y = 0 or, y = 52\frac{5}{2} Both values of y are positive while both values of x are negative. ∴ y > x

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