In the following question, one or two equ… | Answer

Subject

Quantitative Aptitude

Topic

Algebra

In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. $\frac{{{{\left( 2 \right)}^5} + {{\left( {11} \right)}^3}}}{6} = {x^3}$ II. 4y3= - (589 ÷ 4) + 5y3
Reading

ক)

x > y

খ)

x ≥ y

গ)

x < y

ঘ)

x ≤ y

ঙ)

x = y or the relation cannot be determined

Explanation

We will solve both the equations separately. Equation I:

\frac{{{{\left( 2 \right)}^5} + {{\left( {11} \right)}^3}}}{6} = {x^3}

\Rightarrow \frac{{32 + 1331}}{6} = {x^3}

⇒ x 3 = 1363/6 = 227.167 Equation II: 4y 3 = - (589 ÷ 4) + 5y 3 ⇒ 4y 3 = - (589/4) + 5y 3 ⇒ y 3 = 589/4 = 147.25 Comparing the values of x and y we get, x > y

\frac{a}{3} = \frac{b}{4} = \frac{c}{7}

then what would be the value of

\frac{{a + b + c}}{a}

?Multiplication and difference of two numbers are 93 and 28 respectively. Find the difference of reciprocals of the numbers.if

{P^2} + {1 \over {{P^2}}} = 7

, then find the value of

{P^2} - {1 \over {{P^2}}}.

In following question, two equations are given, you have to solve them and choose the correct option: x2– 3x – 4 = 0, y2– 4 = 0 In following question, two equations are given, you have to solve them and chose the correct option: x2+ 11x + 30 = 0, y2+ 7y + 12 = 0 In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘l’ and ‘m’ and mark correct answer. I. (125)1/3l – (1331)1/3= 4 × (729)1/6+ (1024)1/10II. (m)2– (15625)1/3= 0 Direction: In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I: x - √121 = 0 II: y2- 121 = 0 The number of solutions of x2+ 4|x| + 5 = 0 is

Explanation

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