Subject
Quantitative Aptitude
Topic
Algebra
In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer.
I. 8x4– 18x2+ 4 = 0
II. 12y2+ 29y + 14 = 0
In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark correct answer. I. 8x4– 18x2+ 4 = 0 II. 12y2+ 29y + 14 = 0
ক)
x > yখ)
x ≥ yগ)
x < yঘ)
x ≤ yঙ)
x = y or the relation cannot be determinedExplanation
We will solve both the equations separately. Equation I: 8x 4 – 18x 2 + 4 = 0 Let x 2 = a ⇒ 8a 2 –18a + 4 = 0 ⇒ 8a 2 – 16a – 2a + 4 = 0 ⇒ 8a(a – 2) – 2(a – 2) = 0 ⇒ (8a - 2)(a - 2) = 0 ⇒ a = ¼ or a = 2 Since x = √a ∴ x = ±½= ±0.5 or, x = √2 = ±1.41 Equation II: 12y 2 + 29y + 14 = 0 ⇒ 12y 2 + 21y + 8y + 14 = 0 ⇒ 3y(4y + 7) + 2(4y + 7) = 0 ⇒ (3y + 2) (4y + 7) = 0 ⇒ y = -2/3 = -0.67 or y = -7/4 = -1.75 Comparing the values of x and y, we get, Few values of x are greater than y and few are smaller, same is true for y too. So, relation cannot be determined.Related questions
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