Subject
Quantitative Aptitude
Topic
Algebra
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.QuantityA: If a number is as much greater than 53 as it is less than 175, then the number:QuantityB: If and the value of p3+ q3= 45 then the value of (p + q)3/2:
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.QuantityA: If a number is as much greater than 53 as it is less than 175, then the number:QuantityB: If and the value of p3+ q3= 45 then the value of (p + q)3/2:
ক)
Quantity A > Quantity Bখ)
Quantity A < Quantity Bগ)
Quantity A ≥ Quantity Bঘ)
Quantity A ≤ Quantity Bঙ)
Quantity A = Quantity BExplanation
First we will find Quantity A, Quantity A: Let the number be ‘x’. (x – 53) = (175 – x) ⇒ x + x = 175 + 53 ⇒ x = 228/2 = 114 ∴ x = 114 Now, Quantity B: ⇒ p (p – q) = 5 – q 2 ⇒ p 2 – pq + q 2 = 5 ⇒ (p 2 – pq + q 2 ) = 5 We know that, a 3 + b 3 = (a + b)(a 2 – ab + b 2 ) Now, p 3 + q 3 = (p + q)(p 2 – pq + q 2 ) ⇒ 45 = (p + q) × 5 ⇒ (p + q) = 45/5 = 9 ∴ (p+q) 3/2 = 9 3/2 = 27 ∴ Quantity A > Quantity BRelated questions
if then what would be the value of ?Multiplication and difference of two numbers are 93 and 28 respectively. Find the difference of reciprocals of the numbers.if , then find the value of In following question, two equations are given, you have to solve them and choose the correct option:
x2– 3x – 4 = 0,
y2– 4 = 0In following question, two equations are given, you have to solve them and chose the correct option:
x2+ 11x + 30 = 0,
y2+ 7y + 12 = 0In the following question, one or two equation(s) is/are given. You have to solve both the equations and find the relation between ‘l’ and ‘m’ and mark correct answer.
I. (125)1/3l – (1331)1/3= 4 × (729)1/6+ (1024)1/10II. (m)2– (15625)1/3= 0Direction: In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I: x - √121 = 0
II: y2- 121 = 0The number of solutions of x2+ 4|x| + 5 = 0 is
