Subject

    Quantitative Aptitude

    Topic

    Algebra

    Direction:In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I: x2+ 13x + 42 = 0 II: y2+ 16y = - 63

    ক)
    x > y
    খ)
    x ≥ y
    গ)
    x < y
    ঘ)
    x ≤ y
    ঙ)
    x = y or relation cannot be determined

    Explanation

    From equation I: ⇒ x 2 + 13x + 42 = 0 ⇒ (x+6)(x+7) = 0 ⇒ x = -6, -7 From equation II: ⇒ y 2 + 16y + 63 = 0 ⇒ (y+9) (y+7) = 0 ⇒ y = -9, -7 Comparing the value of x and y we get x ≥ y

    Find Tutors

    View all Tutors