Subject
Quantitative Aptitude
Topic
Algebra
Direction:In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I: 2x2+ 11x + 12 = 0
II: 5y2+ 27y + 10 = 0
Direction:In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I: 2x2+ 11x + 12 = 0 II: 5y2+ 27y + 10 = 0
ক)
x > yখ)
x ≥ yগ)
x < yঘ)
x ≤ yঙ)
x = y or relation cannot be determinedExplanation
From equation I: ⇒ 2x 2 + 11x + 12 = 0 ⇒ (x+4)(2x+3) = 0 ⇒ x = -4, -3/2 Given equation II: ⇒ 5y 2 + 27y + 10 = 0 ⇒ (y+5)(5y+2) = 0 ⇒ y = -5, -2/5 Comparing the values of x and y we get, that relation cannot be determined.Related questions
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