Subject
Quantitative Aptitude
Topic
Algebra
Direction: In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I : 5x2– 18x + 9 = 0
II : 20y2– 13y + 2 = 0
Direction: In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:I : 5x2– 18x + 9 = 0 II : 20y2– 13y + 2 = 0
ক)
x > yখ)
x ≥ yগ)
x < yঘ)
x ≤ yঙ)
x = y or relation cannot be determinedExplanation
Given equation I ⇒ 5x 2 – 18 + 9 = 0 ⇒ (5x-3) (x-3) = 0 ⇒ x = 3, 3/5 Given equation II ⇒ 20 y 2 – 13y + 2 = 0 ⇒ (4y -1) (5y - 2) = 0 ⇒ y = ¼, 2/5 Comparing the values of x and y we get x > y.Related questions
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