Subject

    Quantitative Aptitude

    Topic

    Areas & Volumes

    A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is

    ক)
    200m
    খ)
    300m
    গ)
    400m
    ঘ)
    100m

    Explanation

    Let the triangle and parallelogram have common base b, let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then Area of triangle    = 12×b×h1\frac12\times b\times h1 Area of rectangle  = b*h2 As per Given, 12∗b∗h1=b∗h2\frac12\ast b\ast h1=b\ast h2 12∗b∗h1=b∗100\frac12\ast b\ast h1=b\ast100 h1=200

    Find Tutors

    View all Tutors