Subject
Quantitative Aptitude
Topic
Areas & Volumes
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
ক)
2.91 mখ)
3 mগ)
5.82 mঘ)
None of theseExplanation
Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. So, Area of the crossroads = (2400 - 2109) m2 = 291 m2. Let the width of the road be x metres. Then, 60x + 40x - x2 = 291 => x2 - 100x + 291 = 0 => (x - 97)(x - 3) = 0 => x = 3.Related questions
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