Subject

    Quantitative Aptitude

    Topic

    Power & Logarithm

    √(x√(y√z)) = ?

    ক)
    X2y4z8
    খ)
    x1/2y1/4z1/8
    গ)
    √x√y√z
    ঘ)
    x1/2y1/2z1/2

    Explanation

    √(x√(y√z)) = √(x√(y(z1/2))) =√(x(y1/2z1/4)) = x1/2y1/4z1/8

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