Subject
Quantitative Aptitude
Topic
Solution
(xb/xc)(b + c - a). ( xc/ xa)(c + a - b). (xa/ xb)(a + b - c)= ?
(xb/xc)(b + c - a). ( xc/ xa)(c + a - b). (xa/ xb)(a + b - c)= ?
ক)
xabcখ)
1গ)
xab + bc + caঘ)
xa + b + cExplanation
x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c) = x(b - c)(b + c) - a(b - c) . x(c - a)(c + a) - b(c - a) . x(a - b)(a + b) - c(a - b) = x^(b2 - c2 + c2 - a2 + a2 - b2) . x-a(b - c) - b(c - a) - c(a – b) = (x0 x x0) = (1 x 1) = 1.Related questions
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