Subject

    Quantitative Aptitude

    Topic

    Ratio

    if 110:1a=1a:11,{1 \over {10}}:{1 \over a} = {1 \over a}:{1 \over 1},,110:1a=1a:11,then value of a is

    ক)
    \(\sqrt 5\)
    খ)
    \(\sqrt {10}\)
    গ)
    \(2\sqrt 3\)
    ঘ)
    5
    ঙ)
    10

    Explanation

    Given that, \eqalign{ & {{{1 \over {10}}} \over {{1 \over a}}} = {{{1 \over a}} \over 1} \cr & \Rightarrow {a \over {10}} = {1 \over a} \cr & \Rightarrow {a^2} = 10 \cr & \Rightarrow a = \sqrt {10} \cr}

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