Subject

    বিগত বছরের প্রশ্ন

    Topic

    বিসিএস ১৬ তম

    (a2+b2-c2+2ab)/(a2-b2+c2+2ac)=?

    ক)
    a+b+c
    খ)
    (a+b-c)/(a-b+c)
    গ)
    (a-b+c)/(a+b-c)
    ঘ)
    (a+b-c)/(a+b+c)

    Explanation

    (a 2 +b 2 -c 2 +2ab) / (a 2 -b 2 +c 2 +2ac) = [(a + b) 2 - c 2 ] / [(a+c) 2 -b 2 ] = [(a + b + c) (a + b - c)] / [(a + b + c) (a - b + c)] = (a + b - c)/(a - b + c)

    Find Tutors

    View all Tutors