Subject

    Quantitative Aptitude

    Topic

    Simplification

    What will come in place of question mark in the following question? (1−12)(1−13)(1−14)(1−15)…….(1−1x)=?\left( {1 - \frac{1}{2}} \right)\left( {1 - \frac{1}{3}} \right)\left( {1 - \frac{1}{4}} \right)\left( {1 - \frac{1}{5}} \right) \ldots \ldots .\left( {1 - \frac{1}{x}} \right) = ?

    ক)
    (x+1)
    খ)
    (x -1)
    গ)
    (1/x)
    ঘ)
    x
    ঙ)
    None of these

    Explanation

    (1−12)(1−13)(1−14)(1−15)…….(1−1x)=?⇒?=(1−12)(1−13)(1−14)(1−15)…….(1−1x−1)(1−1x)⇒?=12×23×34×…….×(x−2x−1)(x−1x)\begin{array}{l} \left( {1 - \frac{1}{2}} \right)\left( {1 - \frac{1}{3}} \right)\left( {1 - \frac{1}{4}} \right)\left( {1 - \frac{1}{5}} \right) \ldots \ldots .\left( {1 - \frac{1}{x}} \right) = ?\\ \Rightarrow ? = \left( {1 - \frac{1}{2}} \right)\left( {1 - \frac{1}{3}} \right)\left( {1 - \frac{1}{4}} \right)\left( {1 - \frac{1}{5}} \right) \ldots \ldots .\left( {1 - \frac{1}{{x - 1}}} \right)\left( {1 - \frac{1}{x}} \right)\\ \Rightarrow ? = \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} \times \ldots \ldots . \times \left( {\frac{{x - 2}}{{x - 1}}} \right)\left( {\frac{{x - 1}}{x}} \right) \end{array} ⇒ ? = 1/x Hence, the required answer is (1/x)

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