Subject

    Quantitative Aptitude

    Topic

    Number

    What is the square root of 128+262−36128 + \sqrt {262 - \sqrt {36} }

    ক)
    16
    খ)
    18
    গ)
    24
    ঘ)
    12
    ঙ)
    14

    Explanation

    Given expression 128+262−36128 + \sqrt {262 - \sqrt {36} } =128+262−6=128+256\begin{array}{l} = 128 + \sqrt {262 - 6} \\ = 128 + \sqrt {256} \end{array} = 128 + 16 = 144 Now square root of the given expression =144= \sqrt {144} = 12

    Find Tutors

    View all Tutors