Subject
Quantitative Aptitude
Topic
LCM & HCF
What is the minimum number of chocolates that must be added to an existing stock of 966 chocolates, so that the total stock can be equally distributed among 6, 7, 8 or 9 persons?
What is the minimum number of chocolates that must be added to an existing stock of 966 chocolates, so that the total stock can be equally distributed among 6, 7, 8 or 9 persons?
ক)
36খ)
42গ)
56ঘ)
72Explanation
prime factors of following numbers are, 6=2x3 7=1x7 8=2x2x2x2 9=3x3 so,L.C.M=2x3x3x7x4=504Related questions
If HCF(a,b) = 12, LCM(a,b) = 420, and a < b, then a + b = ?The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number isThe HCF of three numbers is 8 and their LCM is 1680. If two of the numbers are 56 and 120, what is the third number?The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:What is the least number when divided by 4,5,6 leaves remainder 3 in each case?If a² - b² = 48 and ab = 140, then what is the HCF(a,b)?The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 isIf 2ⁿ × 3ᵐ × 5ᵖ = 1500, then n + m + p = ?
