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    Subject

    Quantitative Aptitude

    Topic

    Miscellaneous

    Two vessels contain spirit and water mixed respectively in the ratio of 2 : 1 and 3 : 7. Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 7: 9.

    ক)
    5 : 11
    খ)
    3 : 5
    গ)
    5 : 6
    ঘ)
    2 : 1
    ঙ)
    None of the above

    Explanation

    Vessel 1: Spirit : water = 2:1 ∴ Quantity of spirit =  22+1\frac{2}{{2 + 1}} ∴ quantity of spirit in one unit = 2/3 Similarly, quantity of water in one unit = 1/3 Vessel 2 : Spirit : water = 3:7 Therefore quantity of spirit in one unit = 310\frac{3}{{10}} And quantity of water in one unit= 710\frac{7}{{10}} Let vessel 1 and vessel 2 contents be mixed in the ratio x : y Thus according to the new condition, spirit : water = 7 : 9 (x×23)  +(y×  310)(x×13)+(y×710)=79\frac{{\left( {x \times \frac{2}{3}} \right)\; + \left( {y \times \;\frac{3}{{10}}} \right)}}{{\left( {x \times \frac{1}{3}} \right) + \left( {y \times \frac{7}{{10}}} \right)}} = \frac{7}{9} xy=  35\frac{x}{y} = \;\frac{3}{5} Thus the contents of vessel 1 and 2 should be mixed in the ratio 3 : 5

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