Two trains of equal lengths take 10 secon… | Answer

Subject

Quantitative Aptitude

Topic

Speed & Distance

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
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Explanation

Speed of the first train = (120/10) m/sec = 12 m/sec. Speed of the second train = (120/15) m/sec = 8 m/sec. Relative speed = (12 + 8) = 20 m/sec. Therefore, Required time = [(120 + 120)/20] sec = 12 sec.

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Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?Reading

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?

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Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
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