Subject
Quantitative Aptitude
Topic
Speed & Distance
Two trains are travelling in the same direction at 50 km/h and 30 km/h respectively. The faster train crosses a man sitting in the slower train in 18 seconds. Find the length of the faster train.
Two trains are travelling in the same direction at 50 km/h and 30 km/h respectively. The faster train crosses a man sitting in the slower train in 18 seconds. Find the length of the faster train.
ক)
240 metersখ)
180 metersগ)
146 metersঘ)
100 metersঙ)
None of theseExplanation
Relative speed of the faster train with respect to slower train = (50-30) km/h = 20 km/h = 20 × 5/18 m/s =50/9 m/s, Distance travelled by the faster train in crossing the man = length of the faster train (let X), (Note): When a train passes a stationary man/object, the distance travelled by the train would be equal to the length of the train. Now, ∵ Distance = speed × time ⇒ X = (50/9) × 18 = 100 meters.Related questions
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