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    Subject

    Quantitative Aptitude

    Topic

    Speed & Distance

    Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

    ক)
    9 a.m.
    খ)
    10 a.m.
    গ)
    10.30 a.m.
    ঘ)
    11 a.m.

    Explanation

    Given: Distance between stations A and B = 110 km Train from A starts at 7 a.m. with speed = 20 kmph Train from B starts at 8 a.m. with speed = 25 kmph Solution: Let the trains meet x hours after 7 a.m. Distance covered by each train: Train A travels for x hours at 20 kmph Distance = 20x km Train B travels for (x - 1) hours at 25 kmph (since it starts 1 hour later) Distance = 25(x - 1) km Setting up the equation: Since they meet, the sum of distances covered = Total distance 20x + 25(x - 1) = 110 20x + 25x - 25 = 110 45x - 25 = 110 45x = 135 x = 3 Answer: They meet 3 hours after 7 a.m. = 10 a.m. Verification: Train A: 20 × 3 = 60 km Train B: 25 × 2 = 50 km Total: 60 + 50 = 110 km ✓ Therefore, the answer is B) 10 a.m.

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