Subject

    Quantitative Aptitude

    Topic

    Speed & Distance

    Two friends F1and F2go from home to temple and return to home. F1travels through a boat which has speed 20 kmph and river flows at 5 kmph while F2travels by a bullock cart which has speed 24 km/hr. Which one of two return to home first ?

    ক)
    F1
    খ)
    F2
    গ)
    Bothe at same time
    ঘ)
    Data inadequate
    ঙ)
    NONE OF THESE

    Explanation

    Let the distance be ‘D’. Speed of bullock cart = 24 kmph ​Time taken by F 2 in going to temple and back home= Distance/speed = 2 × D/24 = D/12 = 0.083D Speed of boat=20kmph; Speed of stream= 5kmph ​Time taken by F 1 in going to temple and back home =[DUpstream+Ddownstream]=[D20−5+D20+5]=8D75=0.106D= \left[ {\frac{D}{{Upstream}} + \frac{D}{{downstream}}} \right] = \left[ {\frac{D}{{20 - 5}} + \frac{D}{{20 + 5}}} \right] = \frac{{8D}}{{75}} = 0.106D Clearly, F 2 is taking lesser time. Hence, he will reach first.

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