Subject

    Quantitative Aptitude

    Topic

    Probability

    Two dice are tossed. The probability that the total score is a prime number is :

    ক)
    1/6
    খ)
    5/12
    গ)
    1/2
    ঘ)
    7/9
    ঙ)
    None of these

    Explanation

    When S is the sample space, Probability of occurrence of the event, P(E) =Number  of  favorable  outcome,  n(E)Number  of  possible  outcome,  n(S)= \frac{{Number\;of\;favorable\;outcome,\;n\left( E \right)}}{{Number\;of\;possible\;outcome,\;n\left( S \right)}} In a simultaneous throw of two dice, total number of possible combinations = n(S) = 6 × 6 = 36 Let E be the event when the sum of both numbers is a prime number E = {(1, 1), (2, 1), (1, 2), (1, 4), (4, 1), (2, 3), (3, 2), (1, 6), (6, 1), (3, 4), (4, 3), (5, 2), (2, 5), (5, 6), (6, 5)} n(E) = 15 ∴ Probability P(E) = n(E)/n(S) = 15/36 = 5/12

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