Subject
Quantitative Aptitude
Topic
Probability
Two boys are playing a game in which they have to pick balls out of a bag. The bag contains 4 red, 3 green, 2 blue and 5 black balls. If one of the boy draws four balls at random, what is the probability that two are red and two are blue?
Two boys are playing a game in which they have to pick balls out of a bag. The bag contains 4 red, 3 green, 2 blue and 5 black balls. If one of the boy draws four balls at random, what is the probability that two are red and two are blue?
ক)
6/1001খ)
2/1000গ)
6/1500ঘ)
6/1058ঙ)
None of TheseExplanation
Since there are 4 red, 3 green, 2 blue and 5 black balls in the bag, there are a total of 14 balls in the bag. 4 balls are drawn at random; therefore exhaustive number of cases = 14 C 4 Total cases are = 14 C 4 = (14 × 13 × 12 × 11)/(1 × 2 × 3 × 4) = 1001 Now we need to find the case where two are red and two are blue = 4 C 2 × 2 C 2 = 6 × 1 = 6 Therefore the required probability = 6/1001Related questions
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