Subject
Quantitative Aptitude
Topic
Pipes & Cistern
Two Pipes A and B can fill a tank in 6 hours and 4 hours respectively; If they are opened on alternative hours and if pipe A is opened first, in how many hours, the tank shall be full ?
Two Pipes A and B can fill a tank in 6 hours and 4 hours respectively; If they are opened on alternative hours and if pipe A is opened first, in how many hours, the tank shall be full ?
ক)
4খ)
4.5গ)
5ঘ)
5.5Explanation
Solution: (A+B) can fill in first (1+1) = 2 hours 1/6 + 1/4 = (2+3)/12 = 5/12 part. (A+B) can fill next 2 hours = 5/12 part. In first 4 hours the tank fill = 5/12 + 5/12 = 10/12 = 5/6 part. Remaining part 1- 5/6 = 1/6 part. In 5th hour A can fill 1/6 part, So total time 4+1 = 5 hours.Related questions
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