Subject
Quantitative Aptitude
Topic
Probability
Three dice are thrown together.Find the probability of getting a total of atleast 6
Three dice are thrown together.Find the probability of getting a total of atleast 6
ক)
103/216খ)
103/108গ)
103/36ঘ)
36/103Explanation
Total number of events=6 x 6 x 6=216 Let A be the event of getting a total of atleast 6 and B denoted event of getting a total of less than 6 i.e.,3,4,5. So,B={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)} Favourable number of cases=10 Therefore,P(B)=10/216 => P(A) = 1 - P(B) = 1 - (10/216) = 103/108Related questions
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