The value of $ ( 12 - 8 ) ( 3 + 2 ) 5 + 24 $

ঙ) None of these — Numerator : $= ( 12 - 8 ) ( 3 + 2 ) $ $ array l = 2 ( 3 - 2 ) ( 3 + 2 ) \\ = 2 [ ( 3 ) ^2 - ( 2 ) ^2 ] \\ = 2 ( 3 - 2 ) \\ = 2 1 \\ = 2 array $ So, we have $ 2 5 + 24 = 2 5 - 24 25 - 24 $ (Rationalizing the denominator) $ 10 - 4 6 $ $ 4 + 6 - 2 2 6 $ $ ( 6 - 2 )^2 $ $( 6 - 2)$ (Negative value is not considered) Which is not among the given options.

The value of \( ( 12 - 8 ) ( 3 + 2 ) 5 +… | Answer

Subject

Quantitative Aptitude

Topic

Simplification

The value of $\sqrt {\frac{{\left( {\sqrt {12} - \sqrt 8 } \right)\left( {\sqrt 3 + \sqrt 2 } \right)}}{{5 + \sqrt {24} }}}$
Reading

ক)

$\sqrt 2 - \sqrt 6$

খ)

$\sqrt 6 +\sqrt 2$

গ)

$2 +\sqrt 2$

ঘ)

$2 -\sqrt 6$

ঙ)

None of these

Explanation

Numerator :

= \sqrt {{\rm{}}\left( {\sqrt {12} {\rm{}} - {\rm{}}\sqrt 8 } \right)\left( {{\rm{}}\sqrt 3 {\rm{}} + {\rm{}}\sqrt 2 } \right)}

\begin{array}{l} = \sqrt {2{\rm{}} \times \left( {\sqrt 3 - \sqrt 2 } \right) \times \left( {\sqrt 3 {\rm{}} + {\rm{}}\sqrt 2 } \right){\rm{}}} \\ = \sqrt {2 \times \left[ {{\rm{}}{{\left( {\sqrt 3 } \right)}^2} - {{\left( {\sqrt 2 } \right)}^2}{\rm{}}} \right]{\rm{}}} \\ = \sqrt {2{\rm{}} \times {\rm{}}\left( {3{\rm{}} - {\rm{}}2} \right){\rm{}}} \\ = \sqrt {2 \times 1} \\ = \sqrt 2 \end{array}

So, we have

\frac{{\sqrt 2 }}{{\sqrt {5{\rm{}} + {\rm{}}\sqrt {24} } }} = \sqrt 2 \frac{{\sqrt {5{\rm{}} - {\rm{}}\sqrt {24} } {\rm{}}}}{{25 - 24}}

(Rationalizing the denominator)

\sqrt {10{\rm{}} - {\rm{}}4\sqrt 6 }

\sqrt {4 + 6{\rm{}} - {\rm{}}2 \times 2 \times \sqrt 6 }

\sqrt {\left( \sqrt 6 - 2\right)^2 }

(\sqrt 6 - 2)

(Negative value is not considered) Which is not among the given options.

The difference of 1 (3/16) and its reciprocal is equal to What should come in place of question mark (?) in the following question? (43% of 2750) – (38% of 2990) =?How many (1/8)s are there in 37 (1/2)?If

x = \sqrt {\left( {1.96} \right)} - \sqrt {\left( {0.04} \right)}

then the value of x is Find the value -2+(-2)-{-(2)}-2 Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4). The maximum value among the above three is What will come in place of the question mark (?) in the following equation? 160 km 80 m ÷ 6 = ?If I = (3/4) ÷ (5/6), II = 3 ÷ [(4 ÷ 5) ÷ 6], III = [3 ÷ (4 ÷ 5)] ÷ 6, IV = 3 ÷ 4 ÷ (5 ÷ 6), then

The value of (12−8)(3+2)5+24\sqrt {\frac{{\left( {\sqrt {12} - \sqrt 8 } \right)\left( {\sqrt 3 + \sqrt 2 } \right)}}{{5 + \sqrt {24} }}}5+24​(12​−8​)(3​+2​)​​Reading

The value of (12−8)(3+2)5+24\sqrt {\frac{{\left( {\sqrt {12} - \sqrt 8 } \right)\left( {\sqrt 3 + \sqrt 2 } \right)}}{{5 + \sqrt {24} }}}5+24​(12​−8​)(3​+2​)​​

Explanation

Related questions

Find Tutors

The value of $\sqrt {\frac{{\left( {\sqrt {12} - \sqrt 8 } \right)\left( {\sqrt 3 + \sqrt 2 } \right)}}{{5 + \sqrt {24} }}}$
Reading

The value of $\sqrt {\frac{{\left( {\sqrt {12} - \sqrt 8 } \right)\left( {\sqrt 3 + \sqrt 2 } \right)}}{{5 + \sqrt {24} }}}$