Subject

    Quantitative Aptitude

    Topic

    Percentage

    The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ?

    ক)
    Rs.14,000
    খ)
    Rs.12,000
    গ)
    Rs. 12,800
    ঘ)
    Rs. 15,000

    Explanation

    We have P = 8748, R = -10 and n = 3 Therefore, the purchase price of the machine = P(1+R100)n\frac{\mathbf P}{\left(\mathbf1\boldsymbol+{\displaystyle\frac{\mathbf R}{\mathbf{100}}}\right)^\mathbf n} = 8748(1−10100)3\frac{\mathbf{8748}}{\left(\mathbf1\boldsymbol-\frac{\mathbf{10}}{\mathbf{100}}\right)^\mathbf3} = 8748 x (100/90) x (100/90) x (100/90) = 12,000. Therefore, the purchase price of the machine was Rs. 12,000.

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