Subject
Quantitative Aptitude
Topic
Number
The smallest 5 digit number exactly divisible by 41 is:
The smallest 5 digit number exactly divisible by 41 is:
ক)
1004খ)
10004গ)
10045ঘ)
10025Explanation
The smallest 5-digit number = 10000. 41) 10000 (243 82 --- 180 164 ---- 160 123 --- 37 --- Required number = 10000 + (41 - 37) = 10004.Related questions
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:A number is as much greater than 36 as the less than Find the number.If one-third of one-fourth of a number is 15, then three-tenth of that number is:If the number 5 * 2 is divisible by 6, then * =?কাজের দিন ২ টাকা পাওনা এবং অনুপস্থিতির দিন ৫০ পয়সা জরিমানা এই শর্তে সেপ্টেম্বর মাসে ৪০ টাকা পেল। সে কত দিন কাজে উপস্থিত ছিল?476 ** 0 is divisible by both 3 and The non-zero digits in the hundred's and ten's places are respectively:The sum of two numbers is 25 and their difference is Find their product.