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    Subject

    Quantitative Aptitude

    Topic

    Ratio

    The ratio between the time taken by three cars (A, B and C) that travel the same distance is 12 : 15 : 10. If VA=60 km/hr Find VB.

    ক)
    20 km/hr
    খ)
    50 km/hr
    গ)
    72 km/hr
    ঘ)
    60 km/hr
    ঙ)
    48 km/hr

    Explanation

    tA:tB:tC=12:15:10tA=12 K\begin{array}{l} {t_A}:{t_B}:{t_C} = 12:15:10\\ {t_A} = 12\ K \end{array} tB=15 K{t_B} = 15\ K   D = distance tC=10 K{t_C} = 10\ K Speed (v) = Distance/Time ⇒VA:VB:VC=D12k:D15k:D10k=112:115:110⇒VA:VB:VC=5:4:6\begin{array}{l} \Rightarrow {V_A}:{V_B}:{V_C} = \frac{D}{{12k}}:\frac{D}{{15k}}:\frac{D}{{10k}}\\ = \frac{1}{{12}}:\frac{1}{{15}}:\frac{1}{{10}}\\ \Rightarrow {V_A}:{V_B}:{V_C} = {\rm{}}5{\rm{}}:{\rm{}}4{\rm{}}:{\rm{}}6 \end{array} ⇒ V A = 5λ, V B = 4λ, V C = 6λ Given: V A = 60 km/hr = 5λ ⇒ λ = 12 ⇒ V B = 48 km/hr

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