Subject
Quantitative Aptitude
Topic
LCM & HCF
The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is
The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is
ক)
1677খ)
1683গ)
2523ঘ)
3363Explanation
L.C.M of 5, 6, 7, 8 = 840 Therefore, Required Number is of the form 840k+3. Least value of k for which (840k+3) is divisible by 9 is k = 2 Therefore, Required Number = (840 x 2+3)=1683Related questions
If HCF(a,b) = 12, LCM(a,b) = 420, and a < b, then a + b = ?The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number isThe HCF of three numbers is 8 and their LCM is 1680. If two of the numbers are 56 and 120, what is the third number?The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:What is the least number when divided by 4,5,6 leaves remainder 3 in each case?If a² - b² = 48 and ab = 140, then what is the HCF(a,b)?The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 isIf 2ⁿ × 3ᵐ × 5ᵖ = 1500, then n + m + p = ?